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Step 5: Substitute either value (we'll use `+4`) into the `u` bracket expressions, giving us the same roots of the quadratic equation that we found above:įor more on this approach, see: A Different Way to Solve Quadratic Equations (video by Po-Shen Loh). Step 3: Set that expansion equal to the constant term: `1 - u^2 = -15` Step 1: Take −1/2 times the x coefficient. The following approach takes the guesswork out of the factoring step, and is similar to what we'll be doing next, in Completing the Square.
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We could have proceded as follows to solve this quadratic equation. (Similarly, when we substitute `x = -3`, we also get `0`.) Alternate method (Po-Shen Loh's approach) We check the roots in the original equation by Now, if either of the terms ( x − 5) or ( x + 3) is 0, the product is zero. (v) Check the solutions in the original equation
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(iv) Solve the resulting linear equations (i) Bring all terms to the left and simplify, leaving zero on Using the fact that a product is zero if any of its factors is zero we follow these steps: If you need a reminder on how to factor, go back to the section on: Factoring Trinomials. Solving a Quadratic Equation by Factoringįor the time being, we shall deal only with quadratic equations that can be factored (factorised). This can be seen by substituting x = 3 in the The quadratic equation x 2 − 6 x + 9 = 0 has double roots of x = 3 (both roots are the same) In this example, the roots are real and distinct. This can be seen by substituting in the equation: (We'll show below how to find these roots.) The quadratic equation x 2 − 7 x + 10 = 0 has roots of The solution of an equation consists of all numbers (roots) which make the equation true.Īll quadratic equations have 2 solutions (ie.